11450120131 has 2 divisors, whose sum is σ = 11450120132. Its totient is φ = 11450120130.

The previous prime is 11450120113. The next prime is 11450120137. The reversal of 11450120131 is 13102105411.

Together with previous prime (11450120113) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 11450120131 - 2²⁹ = 10913249219 is a prime.

It is a super-2 number, since 2×11450120131² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11450120099 and 11450120108.

It is not a weakly prime, because it can be changed into another prime (11450120137) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5725060065 + 5725060066.

It is an arithmetic number, because the mean of its divisors is an integer number (5725060066).

Almost surely, 2^11450120131 is an apocalyptic number.

11450120131 is a deficient number, since it is larger than the sum of its proper divisors (1).

11450120131 is an equidigital number, since it uses as much as digits as its factorization.

11450120131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 120, while the sum is 19.

Adding to 11450120131 its reverse (13102105411), we get a palindrome (24552225542).

The spelling of 11450120131 in words is "eleven billion, four hundred fifty million, one hundred twenty thousand, one hundred thirty-one".