11450144333 has 4 divisors (see below), whose sum is σ = 11729416188. Its totient is φ = 11170872480.

The previous prime is 11450144291. The next prime is 11450144339. The reversal of 11450144333 is 33344105411.

It is a happy number.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 33344105411 = 59 ⋅565154329.

It can be written as a sum of positive squares in 2 ways, for example, as 2302752169 + 9147392164 = 47987^2 + 95642^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11450144333 is a prime.

It is a super-2 number, since 2×11450144333² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11450144296 and 11450144305.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11450144339) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 139635866 + ... + 139635947.

It is an arithmetic number, because the mean of its divisors is an integer number (2932354047).

Almost surely, 2^11450144333 is an apocalyptic number.

It is an amenable number.

11450144333 is a deficient number, since it is larger than the sum of its proper divisors (279271855).

11450144333 is an equidigital number, since it uses as much as digits as its factorization.

11450144333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 279271854.

The product of its (nonzero) digits is 8640, while the sum is 29.

Adding to 11450144333 its reverse (33344105411), we get a palindrome (44794249744).

The spelling of 11450144333 in words is "eleven billion, four hundred fifty million, one hundred forty-four thousand, three hundred thirty-three".