Base | Representation |
---|---|
bin | 101011101011… |
… | …101011101001 |
3 | 210112202222022 |
4 | 223223223221 |
5 | 10412413423 |
6 | 1045234225 |
7 | 166222112 |
oct | 53535351 |
9 | 23482868 |
10 | 11451113 |
11 | 6511433 |
12 | 3a02975 |
13 | 24ac20b |
14 | 1741209 |
15 | 1012dc8 |
hex | aebae9 |
11451113 has 2 divisors, whose sum is σ = 11451114. Its totient is φ = 11451112.
The previous prime is 11451101. The next prime is 11451119. The reversal of 11451113 is 31115411.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11377129 + 73984 = 3373^2 + 272^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11451113 is a prime.
It is a super-2 number, since 2×114511132 = 262255977877538, which contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11451091 and 11451100.
It is not a weakly prime, because it can be changed into another prime (11451119) by changing a digit.
It is a good prime.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5725556 + 5725557.
It is an arithmetic number, because the mean of its divisors is an integer number (5725557).
Almost surely, 211451113 is an apocalyptic number.
It is an amenable number.
11451113 is a deficient number, since it is larger than the sum of its proper divisors (1).
11451113 is an equidigital number, since it uses as much as digits as its factorization.
11451113 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 60, while the sum is 17.
The square root of 11451113 is about 3383.9493199515. The cubic root of 11451113 is about 225.3975719790.
Adding to 11451113 its reverse (31115411), we get a palindrome (42566524).
The spelling of 11451113 in words is "eleven million, four hundred fifty-one thousand, one hundred thirteen".
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