Base | Representation |
---|---|
bin | 11010000010010110110111… |
… | …100010101110100111010111 |
3 | 120000110011102120202201222111 |
4 | 122002112313202232213113 |
5 | 110002122420304204030 |
6 | 1043313415315411451 |
7 | 33056106226402522 |
oct | 3202266742564727 |
9 | 500404376681874 |
10 | 114511202413015 |
11 | 33539a23508a31 |
12 | 10a15055bb3b87 |
13 | 4bb848b0629c5 |
14 | 203c52c1c3bb9 |
15 | d38a74a2462a |
hex | 6825b78ae9d7 |
114511202413015 has 16 divisors (see below), whose sum is σ = 140770289499840. Its totient is φ = 89371232423680.
The previous prime is 114511202413009. The next prime is 114511202413037. The reversal of 114511202413015 is 510314202115411.
It is a de Polignac number, because none of the positive numbers 2k-114511202413015 is a prime.
It is a super-2 number, since 2×1145112024130152 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 5048635 + ... + 15953404.
It is an arithmetic number, because the mean of its divisors is an integer number (8798143093740).
Almost surely, 2114511202413015 is an apocalyptic number.
114511202413015 is a deficient number, since it is larger than the sum of its proper divisors (26259087086825).
114511202413015 is a wasteful number, since it uses less digits than its factorization.
114511202413015 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 21028682.
The product of its (nonzero) digits is 4800, while the sum is 31.
Adding to 114511202413015 its reverse (510314202115411), we get a palindrome (624825404528426).
The spelling of 114511202413015 in words is "one hundred fourteen trillion, five hundred eleven billion, two hundred two million, four hundred thirteen thousand, fifteen".
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