114511202413037 has 2 divisors, whose sum is σ = 114511202413038. Its totient is φ = 114511202413036.

The previous prime is 114511202413009. The next prime is 114511202413073. The reversal of 114511202413037 is 730314202115411.

Together with next prime (114511202413073) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 111232691049481 + 3278511363556 = 10546691^2 + 1810666^2 .

It is a cyclic number.

It is not a de Polignac number, because 114511202413037 - 2⁶ = 114511202412973 is a prime.

It is a super-2 number, since 2×114511202413037² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 114511202412988 and 114511202413006.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (114511205413037) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57255601206518 + 57255601206519.

It is an arithmetic number, because the mean of its divisors is an integer number (57255601206519).

Almost surely, 2^{114511202413037} is an apocalyptic number.

It is an amenable number.

114511202413037 is a deficient number, since it is larger than the sum of its proper divisors (1).

114511202413037 is an equidigital number, since it uses as much as digits as its factorization.

114511202413037 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 20160, while the sum is 35.

Adding to 114511202413037 its reverse (730314202115411), we get a palindrome (844825404528448).

The spelling of 114511202413037 in words is "one hundred fourteen trillion, five hundred eleven billion, two hundred two million, four hundred thirteen thousand, thirty-seven".