Search a number
-
+
11451134335651 is a prime number
BaseRepresentation
bin1010011010100010110011…
…0010110101101010100011
31111112201101020111102220121
42212220230302311222203
53000103410342220101
640204324542021111
72261213532600163
oct246505462655243
944481336442817
1011451134335651
11371544289053a
12134b381877797
13650ab681532a
142b83489845a3
1514cd0c3120a1
hexa6a2ccb5aa3

11451134335651 has 2 divisors, whose sum is σ = 11451134335652. Its totient is φ = 11451134335650.

The previous prime is 11451134335621. The next prime is 11451134335679. The reversal of 11451134335651 is 15653343115411.

11451134335651 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 11451134335651 - 213 = 11451134327459 is a prime.

It is a super-2 number, since 2×114511343356512 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11451134335598 and 11451134335607.

It is not a weakly prime, because it can be changed into another prime (11451134335621) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5725567167825 + 5725567167826.

It is an arithmetic number, because the mean of its divisors is an integer number (5725567167826).

Almost surely, 211451134335651 is an apocalyptic number.

11451134335651 is a deficient number, since it is larger than the sum of its proper divisors (1).

11451134335651 is an equidigital number, since it uses as much as digits as its factorization.

11451134335651 is an evil number, because the sum of its binary digits is even.

The product of its digits is 324000, while the sum is 43.

The spelling of 11451134335651 in words is "eleven trillion, four hundred fifty-one billion, one hundred thirty-four million, three hundred thirty-five thousand, six hundred fifty-one".