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114513425455153 is a prime number
BaseRepresentation
bin11010000010011000111100…
…000010111101100000110001
3120000110101011111210222111111
4122002120330002331200301
5110002141443404031103
61043314424051113321
733056215302061114
oct3202307402754061
9500411144728444
10114513425455153
113353a96434643a
1210a155765a2841
134bb87537a135a
14203c69d53c57b
15d38b54c9386d
hex68263c0bd831

114513425455153 has 2 divisors, whose sum is σ = 114513425455154. Its totient is φ = 114513425455152.

The previous prime is 114513425455129. The next prime is 114513425455183. The reversal of 114513425455153 is 351554524315411.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 84975635277729 + 29537790177424 = 9218223^2 + 5434868^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-114513425455153 is a prime.

It is a super-2 number, since 2×1145134254551532 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 114513425455097 and 114513425455106.

It is not a weakly prime, because it can be changed into another prime (114513425455103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57256712727576 + 57256712727577.

It is an arithmetic number, because the mean of its divisors is an integer number (57256712727577).

Almost surely, 2114513425455153 is an apocalyptic number.

It is an amenable number.

114513425455153 is a deficient number, since it is larger than the sum of its proper divisors (1).

114513425455153 is an equidigital number, since it uses as much as digits as its factorization.

114513425455153 is an evil number, because the sum of its binary digits is even.

The product of its digits is 3600000, while the sum is 49.

The spelling of 114513425455153 in words is "one hundred fourteen trillion, five hundred thirteen billion, four hundred twenty-five million, four hundred fifty-five thousand, one hundred fifty-three".