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114520304311 = 716360043473
BaseRepresentation
bin110101010100111110…
…0010010101010110111
3101221121010011020011021
41222221330102222313
53334014144214221
6124335423322011
711162630345140
oct1525174225267
9357533136137
10114520304311
11446277a96a6
121a240750307
13aa50b6249a
145785696ac7
152ea3d97041
hex1aa9f12ab7

114520304311 has 4 divisors (see below), whose sum is σ = 130880347792. Its totient is φ = 98160260832.

The previous prime is 114520304287. The next prime is 114520304369. The reversal of 114520304311 is 113403025411.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 114520304311 - 211 = 114520302263 is a prime.

It is a super-2 number, since 2×1145203043112 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (114520304411) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8180021730 + ... + 8180021743.

It is an arithmetic number, because the mean of its divisors is an integer number (32720086948).

Almost surely, 2114520304311 is an apocalyptic number.

114520304311 is a deficient number, since it is larger than the sum of its proper divisors (16360043481).

114520304311 is an equidigital number, since it uses as much as digits as its factorization.

114520304311 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 16360043480.

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 114520304311 its reverse (113403025411), we get a palindrome (227923329722).

The spelling of 114520304311 in words is "one hundred fourteen billion, five hundred twenty million, three hundred four thousand, three hundred eleven".

Divisors: 1 7 16360043473 114520304311