Search a number
-
+
114525211244042 = 257262605622021
BaseRepresentation
bin11010000010100011111010…
…100010001011011000001010
3120000111111120212212002110002
4122002203322202023120022
5110002340113034302132
61043324053345323002
733060113332451504
oct3202437242133012
9500444525762402
10114525211244042
1133544962099035
1210a17905636462
134bb98b1444331
14203d09a918d74
15d390e47ee262
hex6828fa88b60a

114525211244042 has 4 divisors (see below), whose sum is σ = 171787816866066. Its totient is φ = 57262605622020.

The previous prime is 114525211244039. The next prime is 114525211244107. The reversal of 114525211244042 is 240442112525411.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 92075136345241 + 22450074898801 = 9595579^2 + 4738151^2 .

It is a super-3 number, since 3×1145252112440423 (a number of 43 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 114525211243987 and 114525211244005.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28631302811009 + ... + 28631302811012.

Almost surely, 2114525211244042 is an apocalyptic number.

114525211244042 is a deficient number, since it is larger than the sum of its proper divisors (57262605622024).

114525211244042 is an equidigital number, since it uses as much as digits as its factorization.

114525211244042 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 57262605622023.

The product of its (nonzero) digits is 102400, while the sum is 38.

Adding to 114525211244042 its reverse (240442112525411), we get a palindrome (354967323769453).

The spelling of 114525211244042 in words is "one hundred fourteen trillion, five hundred twenty-five billion, two hundred eleven million, two hundred forty-four thousand, forty-two".

Divisors: 1 2 57262605622021 114525211244042