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11453653115323 is a prime number
BaseRepresentation
bin1010011010101100001011…
…1011001110000110111011
31111112221212210000201001121
42212223002323032012323
53000124040144142243
640205422520130111
72261333126063146
oct246530273160673
944487783021047
1011453653115323
113716515650a31
12134b965306937
136510c85bb5c3
142b85072c305d
1514ce084ec1ed
hexa6ac2ece1bb

11453653115323 has 2 divisors, whose sum is σ = 11453653115324. Its totient is φ = 11453653115322.

The previous prime is 11453653115293. The next prime is 11453653115339. The reversal of 11453653115323 is 32351135635411.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 11453653115323 - 237 = 11316214161851 is a prime.

It is a super-3 number, since 3×114536531153233 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a self number, because there is not a number n which added to its sum of digits gives 11453653115323.

It is not a weakly prime, because it can be changed into another prime (11453653115383) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5726826557661 + 5726826557662.

It is an arithmetic number, because the mean of its divisors is an integer number (5726826557662).

Almost surely, 211453653115323 is an apocalyptic number.

11453653115323 is a deficient number, since it is larger than the sum of its proper divisors (1).

11453653115323 is an equidigital number, since it uses as much as digits as its factorization.

11453653115323 is an evil number, because the sum of its binary digits is even.

The product of its digits is 486000, while the sum is 43.

The spelling of 11453653115323 in words is "eleven trillion, four hundred fifty-three billion, six hundred fifty-three million, one hundred fifteen thousand, three hundred twenty-three".