Base | Representation |
---|---|
bin | 11010000010110100100101… |
… | …000111001011010011110011 |
3 | 120000120012202221222012122221 |
4 | 122002310211013023103303 |
5 | 110003133234444032342 |
6 | 1043340213132341511 |
7 | 33061315634651662 |
oct | 3202644507132363 |
9 | 500505687865587 |
10 | 114543105455347 |
11 | 33551504995918 |
12 | 10a1b27a314897 |
13 | 4bbb4a378534a |
14 | 203dcb7288dd9 |
15 | d397e075ca67 |
hex | 682d251cb4f3 |
114543105455347 has 2 divisors, whose sum is σ = 114543105455348. Its totient is φ = 114543105455346.
The previous prime is 114543105455333. The next prime is 114543105455413. The reversal of 114543105455347 is 743554501345411.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-114543105455347 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 114543105455294 and 114543105455303.
It is not a weakly prime, because it can be changed into another prime (114543105455047) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57271552727673 + 57271552727674.
It is an arithmetic number, because the mean of its divisors is an integer number (57271552727674).
Almost surely, 2114543105455347 is an apocalyptic number.
114543105455347 is a deficient number, since it is larger than the sum of its proper divisors (1).
114543105455347 is an equidigital number, since it uses as much as digits as its factorization.
114543105455347 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 10080000, while the sum is 52.
The spelling of 114543105455347 in words is "one hundred fourteen trillion, five hundred forty-three billion, one hundred five million, four hundred fifty-five thousand, three hundred forty-seven".
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