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114543143010119 = 151175806183329
BaseRepresentation
bin11010000010110100100111…
…010110011011111101000111
3120000120012212120122012010102
4122002310213112123331013
5110003133324102310434
61043340220553314315
733061316602114055
oct3202644726337507
9500505776565112
10114543143010119
113355152410631a
1210a1b28aa0599b
134bbb4ab4a3bc5
14203dcbc2631d5
15d397e3bca07e
hex682d2759bf47

114543143010119 has 4 divisors (see below), whose sum is σ = 114618949194960. Its totient is φ = 114467336825280.

The previous prime is 114543143010031. The next prime is 114543143010187. The reversal of 114543143010119 is 911010341345411.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 114543143010119 - 216 = 114543142944583 is a prime.

It is a super-3 number, since 3×1145431430101193 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (114543143010019) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 37903090154 + ... + 37903093175.

It is an arithmetic number, because the mean of its divisors is an integer number (28654737298740).

Almost surely, 2114543143010119 is an apocalyptic number.

114543143010119 is a deficient number, since it is larger than the sum of its proper divisors (75806184841).

114543143010119 is an equidigital number, since it uses as much as digits as its factorization.

114543143010119 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 75806184840.

The product of its (nonzero) digits is 25920, while the sum is 38.

The spelling of 114543143010119 in words is "one hundred fourteen trillion, five hundred forty-three billion, one hundred forty-three million, ten thousand, one hundred nineteen".

Divisors: 1 1511 75806183329 114543143010119