Search a number
-
+
11455014111314 = 25727507055657
BaseRepresentation
bin1010011010110001010000…
…0011000000100001010010
31111120002101121222110120112
42212230110003000201102
53000134332103030224
640210205535041322
72261411633256404
oct246542403004122
944502347873515
1011455014111314
11371705391a404
121350085070242
13651284561987
142b85d5d60b74
1514ce87c3a30e
hexa6b140c0852

11455014111314 has 4 divisors (see below), whose sum is σ = 17182521166974. Its totient is φ = 5727507055656.

The previous prime is 11455014111287. The next prime is 11455014111379. The reversal of 11455014111314 is 41311141055411.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 8491296924289 + 2963717187025 = 2913983^2 + 1721545^2 .

It is a Curzon number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2863753527827 + ... + 2863753527830.

Almost surely, 211455014111314 is an apocalyptic number.

11455014111314 is a deficient number, since it is larger than the sum of its proper divisors (5727507055660).

11455014111314 is an equidigital number, since it uses as much as digits as its factorization.

11455014111314 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5727507055659.

The product of its (nonzero) digits is 4800, while the sum is 32.

Adding to 11455014111314 its reverse (41311141055411), we get a palindrome (52766155166725).

The spelling of 11455014111314 in words is "eleven trillion, four hundred fifty-five billion, fourteen million, one hundred eleven thousand, three hundred fourteen".

Divisors: 1 2 5727507055657 11455014111314