Base | Representation |
---|---|
bin | 1010011010110001010000… |
… | …0011000000100001010010 |
3 | 1111120002101121222110120112 |
4 | 2212230110003000201102 |
5 | 3000134332103030224 |
6 | 40210205535041322 |
7 | 2261411633256404 |
oct | 246542403004122 |
9 | 44502347873515 |
10 | 11455014111314 |
11 | 371705391a404 |
12 | 1350085070242 |
13 | 651284561987 |
14 | 2b85d5d60b74 |
15 | 14ce87c3a30e |
hex | a6b140c0852 |
11455014111314 has 4 divisors (see below), whose sum is σ = 17182521166974. Its totient is φ = 5727507055656.
The previous prime is 11455014111287. The next prime is 11455014111379. The reversal of 11455014111314 is 41311141055411.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 8491296924289 + 2963717187025 = 2913983^2 + 1721545^2 .
It is a Curzon number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2863753527827 + ... + 2863753527830.
Almost surely, 211455014111314 is an apocalyptic number.
11455014111314 is a deficient number, since it is larger than the sum of its proper divisors (5727507055660).
11455014111314 is an equidigital number, since it uses as much as digits as its factorization.
11455014111314 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5727507055659.
The product of its (nonzero) digits is 4800, while the sum is 32.
Adding to 11455014111314 its reverse (41311141055411), we get a palindrome (52766155166725).
The spelling of 11455014111314 in words is "eleven trillion, four hundred fifty-five billion, fourteen million, one hundred eleven thousand, three hundred fourteen".
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