11455141005 has 96 divisors (see below), whose sum is σ = 24788125440. Its totient is φ = 4754211840.

The previous prime is 11455140997. The next prime is 11455141013. The reversal of 11455141005 is 50014155411.

11455141005 is a `hidden beast` number, since 1 + 1 + 4 + 551 + 4 + 100 + 5 = 666.

11455141005 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is an interprime number because it is at equal distance from previous prime (11455140997) and next prime (11455141013).

It is not a de Polignac number, because 11455141005 - 2³ = 11455140997 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 11455141005.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 3300411 + ... + 3303879.

It is an arithmetic number, because the mean of its divisors is an integer number (258209640).

Almost surely, 2^11455141005 is an apocalyptic number.

11455141005 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

It is an amenable number.

11455141005 is an abundant number, since it is smaller than the sum of its proper divisors (13332984435).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11455141005 is a wasteful number, since it uses less digits than its factorization.

11455141005 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4451 (or 4448 counting only the distinct ones).

The product of its (nonzero) digits is 2000, while the sum is 27.

Adding to 11455141005 its reverse (50014155411), we get a palindrome (61469296416).

The spelling of 11455141005 in words is "eleven billion, four hundred fifty-five million, one hundred forty-one thousand, five".