Base | Representation |
---|---|
bin | 110101011010101000… |
… | …1001110011011010011 |
3 | 101222002100202002221102 |
4 | 1222311101032123103 |
5 | 3334411321410311 |
6 | 124410332415015 |
7 | 11200425546005 |
oct | 1526521163323 |
9 | 358070662842 |
10 | 114710341331 |
11 | 44714aa7293 |
12 | 1a29431746b |
13 | aa8133ba21 |
14 | 57a2a04375 |
15 | 2eb58d443b |
hex | 1ab544e6d3 |
114710341331 has 2 divisors, whose sum is σ = 114710341332. Its totient is φ = 114710341330.
The previous prime is 114710341313. The next prime is 114710341379. The reversal of 114710341331 is 133143017411.
Together with previous prime (114710341313) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 114710341331 - 230 = 113636599507 is a prime.
It is a super-2 number, since 2×1147103413312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 114710341294 and 114710341303.
It is not a weakly prime, because it can be changed into another prime (114710341301) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57355170665 + 57355170666.
It is an arithmetic number, because the mean of its divisors is an integer number (57355170666).
Almost surely, 2114710341331 is an apocalyptic number.
114710341331 is a deficient number, since it is larger than the sum of its proper divisors (1).
114710341331 is an equidigital number, since it uses as much as digits as its factorization.
114710341331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3024, while the sum is 29.
Adding to 114710341331 its reverse (133143017411), we get a palindrome (247853358742).
The spelling of 114710341331 in words is "one hundred fourteen billion, seven hundred ten million, three hundred forty-one thousand, three hundred thirty-one".
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