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114713450034 = 23171124641667
BaseRepresentation
bin110101011010101110…
…1000101011000110010
3101222002120121001021120
41222311131011120302
53334413120400114
6124410523203110
711200464144201
oct1526535053062
9358076531246
10114713450034
114471682a967
121a295376496
13aa81b899b1
1457a31b3238
152eb5cea5a9
hex1ab5745632

114713450034 has 16 divisors (see below), whose sum is σ = 242922600288. Its totient is φ = 35988533312.

The previous prime is 114713449999. The next prime is 114713450053. The reversal of 114713450034 is 430054317411.

114713450034 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 114713449977 and 114713450004.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 562320732 + ... + 562320935.

It is an arithmetic number, because the mean of its divisors is an integer number (15182662518).

Almost surely, 2114713450034 is an apocalyptic number.

114713450034 is an abundant number, since it is smaller than the sum of its proper divisors (128209150254).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

114713450034 is a wasteful number, since it uses less digits than its factorization.

114713450034 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1124641689.

The product of its (nonzero) digits is 20160, while the sum is 33.

Adding to 114713450034 its reverse (430054317411), we get a palindrome (544767767445).

The spelling of 114713450034 in words is "one hundred fourteen billion, seven hundred thirteen million, four hundred fifty thousand, thirty-four".

Divisors: 1 2 3 6 17 34 51 102 1124641667 2249283334 3373925001 6747850002 19118908339 38237816678 57356725017 114713450034