Base | Representation |
---|---|
bin | 110101011010101110… |
… | …1000101011000110010 |
3 | 101222002120121001021120 |
4 | 1222311131011120302 |
5 | 3334413120400114 |
6 | 124410523203110 |
7 | 11200464144201 |
oct | 1526535053062 |
9 | 358076531246 |
10 | 114713450034 |
11 | 4471682a967 |
12 | 1a295376496 |
13 | aa81b899b1 |
14 | 57a31b3238 |
15 | 2eb5cea5a9 |
hex | 1ab5745632 |
114713450034 has 16 divisors (see below), whose sum is σ = 242922600288. Its totient is φ = 35988533312.
The previous prime is 114713449999. The next prime is 114713450053. The reversal of 114713450034 is 430054317411.
114713450034 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 114713449977 and 114713450004.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 562320732 + ... + 562320935.
It is an arithmetic number, because the mean of its divisors is an integer number (15182662518).
Almost surely, 2114713450034 is an apocalyptic number.
114713450034 is an abundant number, since it is smaller than the sum of its proper divisors (128209150254).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
114713450034 is a wasteful number, since it uses less digits than its factorization.
114713450034 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1124641689.
The product of its (nonzero) digits is 20160, while the sum is 33.
Adding to 114713450034 its reverse (430054317411), we get a palindrome (544767767445).
The spelling of 114713450034 in words is "one hundred fourteen billion, seven hundred thirteen million, four hundred fifty thousand, thirty-four".
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