Base | Representation |
---|---|
bin | 110101011010101110… |
… | …1000101011001000111 |
3 | 101222002120121001022100 |
4 | 1222311131011121013 |
5 | 3334413120400210 |
6 | 124410523203143 |
7 | 11200464144231 |
oct | 1526535053107 |
9 | 358076531270 |
10 | 114713450055 |
11 | 4471682a986 |
12 | 1a2953764b3 |
13 | aa81b899c9 |
14 | 57a31b3251 |
15 | 2eb5cea5c0 |
hex | 1ab5745647 |
114713450055 has 24 divisors (see below), whose sum is σ = 204210613152. Its totient is φ = 59526978624.
The previous prime is 114713450053. The next prime is 114713450083. The reversal of 114713450055 is 550054317411.
114713450055 is a `hidden beast` number, since 1 + 1 + 4 + 71 + 34 + 500 + 55 = 666.
It is not a de Polignac number, because 114713450055 - 21 = 114713450053 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (114713450053) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 34446819 + ... + 34450148.
It is an arithmetic number, because the mean of its divisors is an integer number (8508775548).
Almost surely, 2114713450055 is an apocalyptic number.
114713450055 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
114713450055 is a deficient number, since it is larger than the sum of its proper divisors (89497163097).
114713450055 is a wasteful number, since it uses less digits than its factorization.
114713450055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 68897015 (or 68897012 counting only the distinct ones).
The product of its (nonzero) digits is 42000, while the sum is 36.
Adding to 114713450055 its reverse (550054317411), we get a palindrome (664767767466).
The spelling of 114713450055 in words is "one hundred fourteen billion, seven hundred thirteen million, four hundred fifty thousand, fifty-five".
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