Base | Representation |
---|---|
bin | 110101011010111011… |
… | …0100001110011101001 |
3 | 101222010001010220210212 |
4 | 1222311312201303221 |
5 | 3334421322320131 |
6 | 124411322150505 |
7 | 11200604634242 |
oct | 1526566416351 |
9 | 358101126725 |
10 | 114720120041 |
11 | 4471a57616a |
12 | 1a297652435 |
13 | aa83383947 |
14 | 57a402bcc9 |
15 | 2eb66b6a2b |
hex | 1ab5da1ce9 |
114720120041 has 2 divisors, whose sum is σ = 114720120042. Its totient is φ = 114720120040.
The previous prime is 114720120029. The next prime is 114720120079. The reversal of 114720120041 is 140021027411.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 97393926400 + 17326193641 = 312080^2 + 131629^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-114720120041 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 114720119989 and 114720120016.
It is not a weakly prime, because it can be changed into another prime (114720120241) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57360060020 + 57360060021.
It is an arithmetic number, because the mean of its divisors is an integer number (57360060021).
Almost surely, 2114720120041 is an apocalyptic number.
It is an amenable number.
114720120041 is a deficient number, since it is larger than the sum of its proper divisors (1).
114720120041 is an equidigital number, since it uses as much as digits as its factorization.
114720120041 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 448, while the sum is 23.
Adding to 114720120041 its reverse (140021027411), we get a palindrome (254741147452).
The spelling of 114720120041 in words is "one hundred fourteen billion, seven hundred twenty million, one hundred twenty thousand, forty-one".
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