Base | Representation |
---|---|
bin | 1101101011100… |
… | …01101011110001 |
3 | 21222221102201102 |
4 | 12311301223301 |
5 | 213334313213 |
6 | 15215414145 |
7 | 2562306344 |
oct | 665615361 |
9 | 258842642 |
10 | 114760433 |
11 | 59863237 |
12 | 32524355 |
13 | 1aa110a8 |
14 | 1135445b |
15 | a11d158 |
hex | 6d71af1 |
114760433 has 2 divisors, whose sum is σ = 114760434. Its totient is φ = 114760432.
The previous prime is 114760411. The next prime is 114760439. The reversal of 114760433 is 334067411.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 96373489 + 18386944 = 9817^2 + 4288^2 .
It is an emirp because it is prime and its reverse (334067411) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 114760433 - 212 = 114756337 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 114760396 and 114760405.
It is not a weakly prime, because it can be changed into another prime (114760439) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57380216 + 57380217.
It is an arithmetic number, because the mean of its divisors is an integer number (57380217).
Almost surely, 2114760433 is an apocalyptic number.
It is an amenable number.
114760433 is a deficient number, since it is larger than the sum of its proper divisors (1).
114760433 is an equidigital number, since it uses as much as digits as its factorization.
114760433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6048, while the sum is 29.
The square root of 114760433 is about 10712.6296024832. The cubic root of 114760433 is about 485.9564969218.
The spelling of 114760433 in words is "one hundred fourteen million, seven hundred sixty thousand, four hundred thirty-three".
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