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114775037155553 is a prime number
BaseRepresentation
bin11010000110001100100101…
…010100011001100011100001
3120001101101102200101100001112
4122012030211110121203201
5110020433234002434203
61044034531341513105
733114136262613605
oct3206144524314341
9501341380340045
10114775037155553
1133630902327aa5
1210a58207872795
134c0731641bc88
14204b1da171505
15d408671cb6d8
hex6863255198e1

114775037155553 has 2 divisors, whose sum is σ = 114775037155554. Its totient is φ = 114775037155552.

The previous prime is 114775037155451. The next prime is 114775037155567. The reversal of 114775037155553 is 355551730577411.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 61667206005409 + 53107831150144 = 7852847^2 + 7287512^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-114775037155553 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 114775037155492 and 114775037155501.

It is not a weakly prime, because it can be changed into another prime (114775037158553) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57387518577776 + 57387518577777.

It is an arithmetic number, because the mean of its divisors is an integer number (57387518577777).

Almost surely, 2114775037155553 is an apocalyptic number.

It is an amenable number.

114775037155553 is a deficient number, since it is larger than the sum of its proper divisors (1).

114775037155553 is an equidigital number, since it uses as much as digits as its factorization.

114775037155553 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 38587500, while the sum is 59.

The spelling of 114775037155553 in words is "one hundred fourteen trillion, seven hundred seventy-five billion, thirty-seven million, one hundred fifty-five thousand, five hundred fifty-three".