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114910351 = 227506213
BaseRepresentation
bin1101101100101…
…10010010001111
322000020001100221
412312112102033
5213404112401
615222532211
72563502413
oct666262217
9260201327
10114910351
1159955936
1232597067
131aa643ba
1411392d43
15a14c7a1
hex6d9648f

114910351 has 4 divisors (see below), whose sum is σ = 115416792. Its totient is φ = 114403912.

The previous prime is 114910349. The next prime is 114910373. The reversal of 114910351 is 153019411.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 153019411 = 214171471.

It is a cyclic number.

It is not a de Polignac number, because 114910351 - 21 = 114910349 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (114910321) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 252880 + ... + 253333.

It is an arithmetic number, because the mean of its divisors is an integer number (28854198).

Almost surely, 2114910351 is an apocalyptic number.

114910351 is a deficient number, since it is larger than the sum of its proper divisors (506441).

114910351 is an equidigital number, since it uses as much as digits as its factorization.

114910351 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 506440.

The product of its (nonzero) digits is 540, while the sum is 25.

The square root of 114910351 is about 10719.6245736500. The cubic root of 114910351 is about 486.1680155987.

Adding to 114910351 its reverse (153019411), we get a palindrome (267929762).

The spelling of 114910351 in words is "one hundred fourteen million, nine hundred ten thousand, three hundred fifty-one".

Divisors: 1 227 506213 114910351