114920137 has 2 divisors, whose sum is σ = 114920138. Its totient is φ = 114920136.

The previous prime is 114920111. The next prime is 114920159. The reversal of 114920137 is 731029411.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 59923081 + 54997056 = 7741^2 + 7416^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-114920137 is a prime.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (114920107) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57460068 + 57460069.

It is an arithmetic number, because the mean of its divisors is an integer number (57460069).

Almost surely, 2^114920137 is an apocalyptic number.

It is an amenable number.

114920137 is a deficient number, since it is larger than the sum of its proper divisors (1).

114920137 is an equidigital number, since it uses as much as digits as its factorization.

114920137 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1512, while the sum is 28.

The square root of 114920137 is about 10720.0810164849. The cubic root of 114920137 is about 486.1818162270.

Adding to 114920137 its reverse (731029411), we get a palindrome (845949548).

The spelling of 114920137 in words is "one hundred fourteen million, nine hundred twenty thousand, one hundred thirty-seven".