Base | Representation |
---|---|
bin | 10101011010001001… |
… | …01011110110110001 |
3 | 1002200000021110011221 |
4 | 22231010223312301 |
5 | 142014331334134 |
6 | 5140300105041 |
7 | 554552111422 |
oct | 125504536661 |
9 | 32600243157 |
10 | 11493621169 |
11 | 4968938778 |
12 | 2289235181 |
13 | 1112288194 |
14 | 7b0685649 |
15 | 4740975b4 |
hex | 2ad12bdb1 |
11493621169 has 2 divisors, whose sum is σ = 11493621170. Its totient is φ = 11493621168.
The previous prime is 11493621149. The next prime is 11493621187. The reversal of 11493621169 is 96112639411.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 8512461169 + 2981160000 = 92263^2 + 54600^2 .
It is a cyclic number.
It is not a de Polignac number, because 11493621169 - 215 = 11493588401 is a prime.
It is a super-2 number, since 2×114936211692 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11493621149) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5746810584 + 5746810585.
It is an arithmetic number, because the mean of its divisors is an integer number (5746810585).
Almost surely, 211493621169 is an apocalyptic number.
It is an amenable number.
11493621169 is a deficient number, since it is larger than the sum of its proper divisors (1).
11493621169 is an equidigital number, since it uses as much as digits as its factorization.
11493621169 is an evil number, because the sum of its binary digits is even.
The product of its digits is 69984, while the sum is 43.
The spelling of 11493621169 in words is "eleven billion, four hundred ninety-three million, six hundred twenty-one thousand, one hundred sixty-nine".
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