Base | Representation |
---|---|
bin | 10101011010001010… |
… | …11110011111001011 |
3 | 1002200000122222122220 |
4 | 22231011132133023 |
5 | 142014410003210 |
6 | 5140304345123 |
7 | 554553634146 |
oct | 125505363713 |
9 | 32600588586 |
10 | 11493828555 |
11 | 4968a6a570 |
12 | 22893151a3 |
13 | 111232b6b1 |
14 | 7b06db05d |
15 | 4740d8c70 |
hex | 2ad15e7cb |
11493828555 has 64 divisors (see below), whose sum is σ = 21688819200. Its totient is φ = 5136721920.
The previous prime is 11493828551. The next prime is 11493828557. The reversal of 11493828555 is 55582839411.
It is not a de Polignac number, because 11493828555 - 22 = 11493828551 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11493828498 and 11493828507.
It is not an unprimeable number, because it can be changed into a prime (11493828551) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 66451 + ... + 165539.
It is an arithmetic number, because the mean of its divisors is an integer number (338887800).
Almost surely, 211493828555 is an apocalyptic number.
11493828555 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
11493828555 is a deficient number, since it is larger than the sum of its proper divisors (10194990645).
11493828555 is a wasteful number, since it uses less digits than its factorization.
11493828555 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 99164.
The product of its digits is 1728000, while the sum is 51.
It can be divided in two parts, 11493 and 828555, that added together give a palindrome (840048).
The spelling of 11493828555 in words is "eleven billion, four hundred ninety-three million, eight hundred twenty-eight thousand, five hundred fifty-five".
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