Base | Representation |
---|---|
bin | 110101100010000111… |
… | …0111100000110101001 |
3 | 101222201212011020000021 |
4 | 1223010032330012221 |
5 | 3340420104301413 |
6 | 124451301440441 |
7 | 11206564531111 |
oct | 1530416740651 |
9 | 358655136007 |
10 | 114961400233 |
11 | 44833793589 |
12 | 1a344410121 |
13 | aac13623a4 |
14 | 57c80b8041 |
15 | 2ecc97718d |
hex | 1ac43bc1a9 |
114961400233 has 4 divisors (see below), whose sum is σ = 117407387520. Its totient is φ = 112515412948.
The previous prime is 114961400201. The next prime is 114961400237. The reversal of 114961400233 is 332004169411.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 114961400233 - 25 = 114961400201 is a prime.
It is a super-2 number, since 2×1149614002332 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (114961400237) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1222993573 + ... + 1222993666.
It is an arithmetic number, because the mean of its divisors is an integer number (29351846880).
Almost surely, 2114961400233 is an apocalyptic number.
It is an amenable number.
114961400233 is a deficient number, since it is larger than the sum of its proper divisors (2445987287).
114961400233 is an equidigital number, since it uses as much as digits as its factorization.
114961400233 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2445987286.
The product of its (nonzero) digits is 15552, while the sum is 34.
Adding to 114961400233 its reverse (332004169411), we get a palindrome (446965569644).
The spelling of 114961400233 in words is "one hundred fourteen billion, nine hundred sixty-one million, four hundred thousand, two hundred thirty-three".
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