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11498306747 is a prime number
BaseRepresentation
bin10101011010101101…
…00011110010111011
31002200100002111120212
422231112203302323
5142022031303442
65140544341335
7554636665124
oct125526436273
932610074525
1011498306747
114970549054
12228a91484b
131113238b05
147b114504b
154746c0a82
hex2ad5a3cbb

11498306747 has 2 divisors, whose sum is σ = 11498306748. Its totient is φ = 11498306746.

The previous prime is 11498306713. The next prime is 11498306761. The reversal of 11498306747 is 74760389411.

It is a strong prime.

It is an emirp because it is prime and its reverse (74760389411) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11498306747 - 228 = 11229871291 is a prime.

It is a super-2 number, since 2×114983067472 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11498306695 and 11498306704.

It is not a weakly prime, because it can be changed into another prime (11498306707) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5749153373 + 5749153374.

It is an arithmetic number, because the mean of its divisors is an integer number (5749153374).

Almost surely, 211498306747 is an apocalyptic number.

11498306747 is a deficient number, since it is larger than the sum of its proper divisors (1).

11498306747 is an equidigital number, since it uses as much as digits as its factorization.

11498306747 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1016064, while the sum is 50.

The spelling of 11498306747 in words is "eleven billion, four hundred ninety-eight million, three hundred six thousand, seven hundred forty-seven".