Base | Representation |
---|---|
bin | 10000101110111001110… |
… | …010001001011110011011 |
3 | 11001221000122021210002101 |
4 | 100232321302021132123 |
5 | 122314420014332003 |
6 | 2240124445144231 |
7 | 146034633632044 |
oct | 20567162113633 |
9 | 4057018253071 |
10 | 1149873199003 |
11 | 403727497631 |
12 | 166a2a25b077 |
13 | 845814ac609 |
14 | 3d92302b8cb |
15 | 1ed9e14a11d |
hex | 10bb9c8979b |
1149873199003 has 2 divisors, whose sum is σ = 1149873199004. Its totient is φ = 1149873199002.
The previous prime is 1149873198911. The next prime is 1149873199049. The reversal of 1149873199003 is 3009913789411.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1149873199003 - 225 = 1149839644571 is a prime.
It is not a weakly prime, because it can be changed into another prime (1149873191003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 574936599501 + 574936599502.
It is an arithmetic number, because the mean of its divisors is an integer number (574936599502).
Almost surely, 21149873199003 is an apocalyptic number.
1149873199003 is a deficient number, since it is larger than the sum of its proper divisors (1).
1149873199003 is an equidigital number, since it uses as much as digits as its factorization.
1149873199003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1469664, while the sum is 55.
The spelling of 1149873199003 in words is "one trillion, one hundred forty-nine billion, eight hundred seventy-three million, one hundred ninety-nine thousand, three".
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