115000040117 has 4 divisors (see below), whose sum is σ = 115009601280. Its totient is φ = 114990478956.

The previous prime is 115000040069. The next prime is 115000040119. The reversal of 115000040117 is 711040000511.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 115000040117 - 2²² = 114995845813 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (115000040119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4762517 + ... + 4786602.

It is an arithmetic number, because the mean of its divisors is an integer number (28752400320).

Almost surely, 2^115000040117 is an apocalyptic number.

It is an amenable number.

115000040117 is a deficient number, since it is larger than the sum of its proper divisors (9561163).

115000040117 is an equidigital number, since it uses as much as digits as its factorization.

115000040117 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9561162.

The product of its (nonzero) digits is 140, while the sum is 20.

Adding to 115000040117 its reverse (711040000511), we get a palindrome (826040040628).

The spelling of 115000040117 in words is "one hundred fifteen billion, forty thousand, one hundred seventeen".