Base | Representation |
---|---|
bin | 11010001001011111001101… |
… | …101011001111011100101011 |
3 | 120002012000012100200222211201 |
4 | 122021133031223033130223 |
5 | 110033134424200441042 |
6 | 1044330453312505031 |
7 | 33136363641322315 |
oct | 3211371553173453 |
9 | 502160170628751 |
10 | 115001200015147 |
11 | 3370880a373906 |
12 | 10a9400524b177 |
13 | 4c22749b63a54 |
14 | 2058132c1c7b5 |
15 | d466a24741b7 |
hex | 6897cdacf72b |
115001200015147 has 2 divisors, whose sum is σ = 115001200015148. Its totient is φ = 115001200015146.
The previous prime is 115001200015123. The next prime is 115001200015193. The reversal of 115001200015147 is 741510002100511.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-115001200015147 is a prime.
It is not a weakly prime, because it can be changed into another prime (115001200015747) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57500600007573 + 57500600007574.
It is an arithmetic number, because the mean of its divisors is an integer number (57500600007574).
Almost surely, 2115001200015147 is an apocalyptic number.
115001200015147 is a deficient number, since it is larger than the sum of its proper divisors (1).
115001200015147 is an equidigital number, since it uses as much as digits as its factorization.
115001200015147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1400, while the sum is 28.
Adding to 115001200015147 its reverse (741510002100511), we get a palindrome (856511202115658).
The spelling of 115001200015147 in words is "one hundred fifteen trillion, one billion, two hundred million, fifteen thousand, one hundred forty-seven".
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