Base | Representation |
---|---|
bin | 11010001001100000001111… |
… | …011001000011011001010101 |
3 | 120002012010001012022020100010 |
4 | 122021200033121003121111 |
5 | 110033144203422342240 |
6 | 1044331154535510433 |
7 | 33136433156545452 |
oct | 3211401731033125 |
9 | 502163035266303 |
10 | 115002302543445 |
11 | 33709225755719 |
12 | 10a94272528419 |
13 | 4c228943bb465 |
14 | 20581d9418829 |
15 | d46719159280 |
hex | 68980f643655 |
115002302543445 has 16 divisors (see below), whose sum is σ = 194827430191680. Its totient is φ = 57726645982464.
The previous prime is 115002302543369. The next prime is 115002302543503. The reversal of 115002302543445 is 544345203200511.
It is not a de Polignac number, because 115002302543445 - 211 = 115002302541397 is a prime.
It is a super-2 number, since 2×1150023025434452 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 225494710615 + ... + 225494711124.
It is an arithmetic number, because the mean of its divisors is an integer number (12176714386980).
Almost surely, 2115002302543445 is an apocalyptic number.
115002302543445 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
115002302543445 is a deficient number, since it is larger than the sum of its proper divisors (79825127648235).
115002302543445 is a wasteful number, since it uses less digits than its factorization.
115002302543445 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 450989421764.
The product of its (nonzero) digits is 288000, while the sum is 39.
Adding to 115002302543445 its reverse (544345203200511), we get a palindrome (659347505743956).
The spelling of 115002302543445 in words is "one hundred fifteen trillion, two billion, three hundred two million, five hundred forty-three thousand, four hundred forty-five".
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