Base | Representation |
---|---|
bin | 10101011010111011… |
… | …11010010010110011 |
3 | 1002200110201102011011 |
4 | 22231131322102303 |
5 | 142023024441112 |
6 | 5141053531351 |
7 | 554662242511 |
oct | 125535722263 |
9 | 32613642134 |
10 | 11500233907 |
11 | 4971644a48 |
12 | 228b4a3b57 |
13 | 1113762046 |
14 | 7b14c74b1 |
15 | 474951aa7 |
hex | 2ad77a4b3 |
11500233907 has 2 divisors, whose sum is σ = 11500233908. Its totient is φ = 11500233906.
The previous prime is 11500233817. The next prime is 11500233917. The reversal of 11500233907 is 70933200511.
It is a strong prime.
It is an emirp because it is prime and its reverse (70933200511) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11500233907 - 231 = 9352750259 is a prime.
It is not a weakly prime, because it can be changed into another prime (11500233917) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5750116953 + 5750116954.
It is an arithmetic number, because the mean of its divisors is an integer number (5750116954).
Almost surely, 211500233907 is an apocalyptic number.
11500233907 is a deficient number, since it is larger than the sum of its proper divisors (1).
11500233907 is an equidigital number, since it uses as much as digits as its factorization.
11500233907 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5670, while the sum is 31.
The spelling of 11500233907 in words is "eleven billion, five hundred million, two hundred thirty-three thousand, nine hundred seven".
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