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1150035423 = 3383345141
BaseRepresentation
bin100010010001100…
…0010010111011111
32222010222212000120
41010203002113133
54323402113143
6310041130023
740333065645
oct10443022737
92863885016
101150035423
1154018a6a9
12281189913
1315434c244
14aca45195
156ae6b383
hex448c25df

1150035423 has 4 divisors (see below), whose sum is σ = 1533380568. Its totient is φ = 766690280.

The previous prime is 1150035413. The next prime is 1150035451. The reversal of 1150035423 is 3245300511.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1150035423 - 212 = 1150031327 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1150035393 and 1150035402.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1150035413) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 191672568 + ... + 191672573.

It is an arithmetic number, because the mean of its divisors is an integer number (383345142).

Almost surely, 21150035423 is an apocalyptic number.

1150035423 is a deficient number, since it is larger than the sum of its proper divisors (383345145).

1150035423 is an equidigital number, since it uses as much as digits as its factorization.

1150035423 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 383345144.

The product of its (nonzero) digits is 1800, while the sum is 24.

The square root of 1150035423 is about 33912.1721952458. The cubic root of 1150035423 is about 1047.7003102516.

Adding to 1150035423 its reverse (3245300511), we get a palindrome (4395335934).

The spelling of 1150035423 in words is "one billion, one hundred fifty million, thirty-five thousand, four hundred twenty-three".

Divisors: 1 3 383345141 1150035423