Base | Representation |
---|---|
bin | 100010010001100… |
… | …0011110010011001 |
3 | 2222011000011000001 |
4 | 1010203003302121 |
5 | 4323402304431 |
6 | 310041213001 |
7 | 40333121626 |
oct | 10443036231 |
9 | 2864004001 |
10 | 1150041241 |
11 | 540194008 |
12 | 281191161 |
13 | 154351a9b |
14 | aca4734d |
15 | 6ae6ce61 |
hex | 448c3c99 |
1150041241 has 2 divisors, whose sum is σ = 1150041242. Its totient is φ = 1150041240.
The previous prime is 1150041229. The next prime is 1150041251. The reversal of 1150041241 is 1421400511.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 723825216 + 426216025 = 26904^2 + 20645^2 .
It is a cyclic number.
It is not a de Polignac number, because 1150041241 - 25 = 1150041209 is a prime.
It is not a weakly prime, because it can be changed into another prime (1150041251) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 575020620 + 575020621.
It is an arithmetic number, because the mean of its divisors is an integer number (575020621).
Almost surely, 21150041241 is an apocalyptic number.
It is an amenable number.
1150041241 is a deficient number, since it is larger than the sum of its proper divisors (1).
1150041241 is an equidigital number, since it uses as much as digits as its factorization.
1150041241 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 160, while the sum is 19.
The square root of 1150041241 is about 33912.2579755462. The cubic root of 1150041241 is about 1047.7020770118.
Adding to 1150041241 its reverse (1421400511), we get a palindrome (2571441752).
The spelling of 1150041241 in words is "one billion, one hundred fifty million, forty-one thousand, two hundred forty-one".
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