115004142403303 has 4 divisors (see below), whose sum is σ = 115118120741680. Its totient is φ = 114890164064928.

The previous prime is 115004142403291. The next prime is 115004142403309. The reversal of 115004142403303 is 303304241400511.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 115004142403303 - 2¹³ = 115004142395111 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (115004142403309) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 56989167675 + ... + 56989169692.

It is an arithmetic number, because the mean of its divisors is an integer number (28779530185420).

Almost surely, 2^{115004142403303} is an apocalyptic number.

115004142403303 is a deficient number, since it is larger than the sum of its proper divisors (113978338377).

115004142403303 is a wasteful number, since it uses less digits than its factorization.

115004142403303 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 113978338376.

The product of its (nonzero) digits is 17280, while the sum is 31.

Adding to 115004142403303 its reverse (303304241400511), we get a palindrome (418308383803814).

The spelling of 115004142403303 in words is "one hundred fifteen trillion, four billion, one hundred forty-two million, four hundred three thousand, three hundred three".