Base | Representation |
---|---|
bin | 11010001001100001111101… |
… | …000011100011111011101101 |
3 | 120002012021210102022210121001 |
4 | 122021201331003203323231 |
5 | 110033211440423401214 |
6 | 1044332101302240301 |
7 | 33136526600235415 |
oct | 3211417503437355 |
9 | 502167712283531 |
10 | 115004142403309 |
11 | 33709a8a264665 |
12 | 10a946a6726091 |
13 | 4c22ac8626333 |
14 | 2058331909645 |
15 | d467c5937c74 |
hex | 68987d0e3eed |
115004142403309 has 2 divisors, whose sum is σ = 115004142403310. Its totient is φ = 115004142403308.
The previous prime is 115004142403291. The next prime is 115004142403327. The reversal of 115004142403309 is 903304241400511.
It is a balanced prime because it is at equal distance from previous prime (115004142403291) and next prime (115004142403327).
It can be written as a sum of positive squares in only one way, i.e., 114631069428100 + 373072975209 = 10706590^2 + 610797^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-115004142403309 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (115004142403379) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57502071201654 + 57502071201655.
It is an arithmetic number, because the mean of its divisors is an integer number (57502071201655).
Almost surely, 2115004142403309 is an apocalyptic number.
It is an amenable number.
115004142403309 is a deficient number, since it is larger than the sum of its proper divisors (1).
115004142403309 is an equidigital number, since it uses as much as digits as its factorization.
115004142403309 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 51840, while the sum is 37.
The spelling of 115004142403309 in words is "one hundred fifteen trillion, four billion, one hundred forty-two million, four hundred three thousand, three hundred nine".
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