Base | Representation |
---|---|
bin | 100010010001100… |
… | …0110010001101001 |
3 | 2222011000122222112 |
4 | 1010203012101221 |
5 | 4323403121213 |
6 | 310041332105 |
7 | 40333163426 |
oct | 10443062151 |
9 | 2864018875 |
10 | 1150051433 |
11 | 5401a0733 |
12 | 281197035 |
13 | 15435660b |
14 | aca4ad4d |
15 | 6ae70ea8 |
hex | 448c6469 |
1150051433 has 2 divisors, whose sum is σ = 1150051434. Its totient is φ = 1150051432.
The previous prime is 1150051391. The next prime is 1150051439. The reversal of 1150051433 is 3341500511.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1148057689 + 1993744 = 33883^2 + 1412^2 .
It is a cyclic number.
It is not a de Polignac number, because 1150051433 - 210 = 1150050409 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1150051399 and 1150051408.
It is not a weakly prime, because it can be changed into another prime (1150051439) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 575025716 + 575025717.
It is an arithmetic number, because the mean of its divisors is an integer number (575025717).
Almost surely, 21150051433 is an apocalyptic number.
It is an amenable number.
1150051433 is a deficient number, since it is larger than the sum of its proper divisors (1).
1150051433 is an equidigital number, since it uses as much as digits as its factorization.
1150051433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 900, while the sum is 23.
The square root of 1150051433 is about 33912.4082453606. The cubic root of 1150051433 is about 1047.7051720161.
Adding to 1150051433 its reverse (3341500511), we get a palindrome (4491551944).
The spelling of 1150051433 in words is "one billion, one hundred fifty million, fifty-one thousand, four hundred thirty-three".
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