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11500532053 = 103111655651
BaseRepresentation
bin10101011010111110…
…00011000101010101
31002200111021120010121
422231133003011111
5142023114011203
65141104151541
7554664623653
oct125537030525
932614246117
1011500532053
114971828a4a
12228b6085b1
13111383796a
147b1563dd3
154749b00bd
hex2ad7c3155

11500532053 has 4 divisors (see below), whose sum is σ = 11612187808. Its totient is φ = 11388876300.

The previous prime is 11500532027. The next prime is 11500532101. The reversal of 11500532053 is 35023500511.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11500532053 - 29 = 11500531541 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11500532003) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 55827723 + ... + 55827928.

It is an arithmetic number, because the mean of its divisors is an integer number (2903046952).

Almost surely, 211500532053 is an apocalyptic number.

It is an amenable number.

11500532053 is a deficient number, since it is larger than the sum of its proper divisors (111655755).

11500532053 is a wasteful number, since it uses less digits than its factorization.

11500532053 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 111655754.

The product of its (nonzero) digits is 2250, while the sum is 25.

The spelling of 11500532053 in words is "eleven billion, five hundred million, five hundred thirty-two thousand, fifty-three".

Divisors: 1 103 111655651 11500532053