Base | Representation |
---|---|
bin | 11010001001100111011010… |
… | …110110100011111110011011 |
3 | 120002012211221102011110220122 |
4 | 122021213122312203332123 |
5 | 110033311000310134321 |
6 | 1044334511503143455 |
7 | 33140125200535535 |
oct | 3211473266437633 |
9 | 502184842143818 |
10 | 115010011021211 |
11 | 33711520a0a0a9 |
12 | 10a95863ba4b8b |
13 | 4c235224114c7 |
14 | 205872b0b8855 |
15 | d46a1ac6c8ab |
hex | 6899dada3f9b |
115010011021211 has 2 divisors, whose sum is σ = 115010011021212. Its totient is φ = 115010011021210.
The previous prime is 115010011021207. The next prime is 115010011021231. The reversal of 115010011021211 is 112120110010511.
It is a weak prime.
It is an emirp because it is prime and its reverse (112120110010511) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 115010011021211 - 22 = 115010011021207 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 115010011021211.
It is not a weakly prime, because it can be changed into another prime (115010011021231) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57505005510605 + 57505005510606.
It is an arithmetic number, because the mean of its divisors is an integer number (57505005510606).
Almost surely, 2115010011021211 is an apocalyptic number.
115010011021211 is a deficient number, since it is larger than the sum of its proper divisors (1).
115010011021211 is an equidigital number, since it uses as much as digits as its factorization.
115010011021211 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 20, while the sum is 17.
Adding to 115010011021211 its reverse (112120110010511), we get a palindrome (227130121031722).
The spelling of 115010011021211 in words is "one hundred fifteen trillion, ten billion, eleven million, twenty-one thousand, two hundred eleven".
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