1150105433 has 2 divisors, whose sum is σ = 1150105434. Its totient is φ = 1150105432.

The previous prime is 1150105423. The next prime is 1150105457. The reversal of 1150105433 is 3345010511.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1060935184 + 89170249 = 32572^2 + 9443^2 .

It is an emirp because it is prime and its reverse (3345010511) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1150105433 - 2¹⁶ = 1150039897 is a prime.

It is a super-2 number, since 2×1150105433² = 2645485014032234978, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1150105399 and 1150105408.

It is not a weakly prime, because it can be changed into another prime (1150105423) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 575052716 + 575052717.

It is an arithmetic number, because the mean of its divisors is an integer number (575052717).

Almost surely, 2^1150105433 is an apocalyptic number.

It is an amenable number.

1150105433 is a deficient number, since it is larger than the sum of its proper divisors (1).

1150105433 is an equidigital number, since it uses as much as digits as its factorization.

1150105433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 900, while the sum is 23.

The square root of 1150105433 is about 33913.2044047743. The cubic root of 1150105433 is about 1047.7215698897.

Adding to 1150105433 its reverse (3345010511), we get a palindrome (4495115944).

The spelling of 1150105433 in words is "one billion, one hundred fifty million, one hundred five thousand, four hundred thirty-three".