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115011200132151 = 338337066710717
BaseRepresentation
bin11010001001101000100001…
…101110101010010000110111
3120002012222000021200120110120
4122021220201232222100313
5110033320414213212101
61044335225502023023
733140166520032351
oct3211504156522067
9502188007616416
10115011200132151
1133711a81158814
1210a95b36277a73
134c2368189254b
142058800db20d1
15d46a8a356b36
hex689a21baa437

115011200132151 has 4 divisors (see below), whose sum is σ = 153348266842872. Its totient is φ = 76674133421432.

The previous prime is 115011200132131. The next prime is 115011200132167. The reversal of 115011200132151 is 151231002110511.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 115011200132151 - 234 = 114994020262967 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (115011200132131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 19168533355356 + ... + 19168533355361.

It is an arithmetic number, because the mean of its divisors is an integer number (38337066710718).

Almost surely, 2115011200132151 is an apocalyptic number.

115011200132151 is a deficient number, since it is larger than the sum of its proper divisors (38337066710721).

115011200132151 is an equidigital number, since it uses as much as digits as its factorization.

115011200132151 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 38337066710720.

The product of its (nonzero) digits is 300, while the sum is 24.

Adding to 115011200132151 its reverse (151231002110511), we get a palindrome (266242202242662).

The spelling of 115011200132151 in words is "one hundred fifteen trillion, eleven billion, two hundred million, one hundred thirty-two thousand, one hundred fifty-one".

Divisors: 1 3 38337066710717 115011200132151