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115012433 is a prime number
BaseRepresentation
bin1101101101011…
…11001101010001
322000102020101202
412312233031101
5213420344213
615225040545
72564406134
oct666571521
9260366352
10115012433
1159a155a8
1232626155
131aa9b9c3
14113bc21b
15a16cb58
hex6daf351

115012433 has 2 divisors, whose sum is σ = 115012434. Its totient is φ = 115012432.

The previous prime is 115012427. The next prime is 115012451. The reversal of 115012433 is 334210511.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 103876864 + 11135569 = 10192^2 + 3337^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-115012433 is a prime.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (115012423) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57506216 + 57506217.

It is an arithmetic number, because the mean of its divisors is an integer number (57506217).

Almost surely, 2115012433 is an apocalyptic number.

It is an amenable number.

115012433 is a deficient number, since it is larger than the sum of its proper divisors (1).

115012433 is an equidigital number, since it uses as much as digits as its factorization.

115012433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 360, while the sum is 20.

The square root of 115012433 is about 10724.3849707104. The cubic root of 115012433 is about 486.3119374009.

Adding to 115012433 its reverse (334210511), we get a palindrome (449222944).

The spelling of 115012433 in words is "one hundred fifteen million, twelve thousand, four hundred thirty-three".