Base | Representation |
---|---|
bin | 10101011011000101… |
… | …00011101011000011 |
3 | 1002200120000022000122 |
4 | 22231202203223003 |
5 | 142023332430341 |
6 | 5141140010455 |
7 | 555005504642 |
oct | 125542435303 |
9 | 32616008018 |
10 | 11501451971 |
11 | 49722a7109 |
12 | 228b990a2b |
13 | 1113a9a5a9 |
14 | 7b1723359 |
15 | 474ae294b |
hex | 2ad8a3ac3 |
11501451971 has 2 divisors, whose sum is σ = 11501451972. Its totient is φ = 11501451970.
The previous prime is 11501451953. The next prime is 11501452009. The reversal of 11501451971 is 17915410511.
11501451971 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11501451971 - 214 = 11501435587 is a prime.
It is not a weakly prime, because it can be changed into another prime (11501451901) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5750725985 + 5750725986.
It is an arithmetic number, because the mean of its divisors is an integer number (5750725986).
Almost surely, 211501451971 is an apocalyptic number.
11501451971 is a deficient number, since it is larger than the sum of its proper divisors (1).
11501451971 is an equidigital number, since it uses as much as digits as its factorization.
11501451971 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6300, while the sum is 35.
The spelling of 11501451971 in words is "eleven billion, five hundred one million, four hundred fifty-one thousand, nine hundred seventy-one".
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