11502243341 has 4 divisors (see below), whose sum is σ = 11505457152. Its totient is φ = 11499029532.

The previous prime is 11502243331. The next prime is 11502243353. The reversal of 11502243341 is 14334220511.

It is a happy number.

11502243341 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 14334220511 = 13 ⋅1102632347.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11502243341 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 11502243341.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11502243331) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1601531 + ... + 1608696.

It is an arithmetic number, because the mean of its divisors is an integer number (2876364288).

Almost surely, 2^11502243341 is an apocalyptic number.

It is an amenable number.

11502243341 is a deficient number, since it is larger than the sum of its proper divisors (3213811).

11502243341 is an equidigital number, since it uses as much as digits as its factorization.

11502243341 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3213810.

The product of its (nonzero) digits is 2880, while the sum is 26.

Adding to 11502243341 its reverse (14334220511), we get a palindrome (25836463852).

The spelling of 11502243341 in words is "eleven billion, five hundred two million, two hundred forty-three thousand, three hundred forty-one".