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115030141526051 is a prime number
BaseRepresentation
bin11010001001111010001010…
…101110010110000000100011
3120002021202220100021002010222
4122021322022232112000203
5110034123212212313201
61044352041213513255
733141440066155163
oct3211721256260043
9502252810232128
10115030141526051
113371a011075364
1210a997417a282b
134c253acb5062b
1420596ba8525a3
15d472e81b691b
hex689e8ab96023

115030141526051 has 2 divisors, whose sum is σ = 115030141526052. Its totient is φ = 115030141526050.

The previous prime is 115030141526017. The next prime is 115030141526089. The reversal of 115030141526051 is 150625141030511.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 115030141526051 - 26 = 115030141525987 is a prime.

It is a super-2 number, since 2×1150301415260512 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (115030141520051) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57515070763025 + 57515070763026.

It is an arithmetic number, because the mean of its divisors is an integer number (57515070763026).

Almost surely, 2115030141526051 is an apocalyptic number.

115030141526051 is a deficient number, since it is larger than the sum of its proper divisors (1).

115030141526051 is an equidigital number, since it uses as much as digits as its factorization.

115030141526051 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 18000, while the sum is 35.

Adding to 115030141526051 its reverse (150625141030511), we get a palindrome (265655282556562).

The spelling of 115030141526051 in words is "one hundred fifteen trillion, thirty billion, one hundred forty-one million, five hundred twenty-six thousand, fifty-one".