Base | Representation |
---|---|
bin | 11010001001111010001010… |
… | …101110010110000000100011 |
3 | 120002021202220100021002010222 |
4 | 122021322022232112000203 |
5 | 110034123212212313201 |
6 | 1044352041213513255 |
7 | 33141440066155163 |
oct | 3211721256260043 |
9 | 502252810232128 |
10 | 115030141526051 |
11 | 3371a011075364 |
12 | 10a997417a282b |
13 | 4c253acb5062b |
14 | 20596ba8525a3 |
15 | d472e81b691b |
hex | 689e8ab96023 |
115030141526051 has 2 divisors, whose sum is σ = 115030141526052. Its totient is φ = 115030141526050.
The previous prime is 115030141526017. The next prime is 115030141526089. The reversal of 115030141526051 is 150625141030511.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 115030141526051 - 26 = 115030141525987 is a prime.
It is a super-2 number, since 2×1150301415260512 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (115030141520051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57515070763025 + 57515070763026.
It is an arithmetic number, because the mean of its divisors is an integer number (57515070763026).
Almost surely, 2115030141526051 is an apocalyptic number.
115030141526051 is a deficient number, since it is larger than the sum of its proper divisors (1).
115030141526051 is an equidigital number, since it uses as much as digits as its factorization.
115030141526051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 18000, while the sum is 35.
Adding to 115030141526051 its reverse (150625141030511), we get a palindrome (265655282556562).
The spelling of 115030141526051 in words is "one hundred fifteen trillion, thirty billion, one hundred forty-one million, five hundred twenty-six thousand, fifty-one".
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