Base | Representation |
---|---|
bin | 11010001001111010001010… |
… | …101111111001101010100011 |
3 | 120002021202220101000211002012 |
4 | 122021322022233321222203 |
5 | 110034123212313343433 |
6 | 1044352041230343135 |
7 | 33141440102505224 |
oct | 3211721257715243 |
9 | 502252811024065 |
10 | 115030141934243 |
11 | 3371a011324008 |
12 | 10a9974195aaab |
13 | 4c253acc64373 |
14 | 20596ba91b24b |
15 | d472e8247848 |
hex | 689e8abf9aa3 |
115030141934243 has 2 divisors, whose sum is σ = 115030141934244. Its totient is φ = 115030141934242.
The previous prime is 115030141934233. The next prime is 115030141934293. The reversal of 115030141934243 is 342439141030511.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 115030141934243 - 26 = 115030141934179 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 115030141934243.
It is not a weakly prime, because it can be changed into another prime (115030141934233) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57515070967121 + 57515070967122.
It is an arithmetic number, because the mean of its divisors is an integer number (57515070967122).
Almost surely, 2115030141934243 is an apocalyptic number.
115030141934243 is a deficient number, since it is larger than the sum of its proper divisors (1).
115030141934243 is an equidigital number, since it uses as much as digits as its factorization.
115030141934243 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 155520, while the sum is 41.
Adding to 115030141934243 its reverse (342439141030511), we get a palindrome (457469282964754).
The spelling of 115030141934243 in words is "one hundred fifteen trillion, thirty billion, one hundred forty-one million, nine hundred thirty-four thousand, two hundred forty-three".
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