Base | Representation |
---|---|
bin | 11010001001111100000110… |
… | …010111010010001100110011 |
3 | 120002021222020220110221210021 |
4 | 122021330012113102030303 |
5 | 110034141434224342143 |
6 | 1044353023113544311 |
7 | 33141542354526142 |
oct | 3211740627221463 |
9 | 502258226427707 |
10 | 115032215855923 |
11 | 3371a985a70073 |
12 | 10a9a020415097 |
13 | 4c25650821262 |
14 | 2059836139759 |
15 | d473ba35cced |
hex | 689f065d2333 |
115032215855923 has 2 divisors, whose sum is σ = 115032215855924. Its totient is φ = 115032215855922.
The previous prime is 115032215855881. The next prime is 115032215855941. The reversal of 115032215855923 is 329558512230511.
It is a strong prime.
It is an emirp because it is prime and its reverse (329558512230511) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 115032215855923 - 217 = 115032215724851 is a prime.
It is not a weakly prime, because it can be changed into another prime (115032215855423) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57516107927961 + 57516107927962.
It is an arithmetic number, because the mean of its divisors is an integer number (57516107927962).
Almost surely, 2115032215855923 is an apocalyptic number.
115032215855923 is a deficient number, since it is larger than the sum of its proper divisors (1).
115032215855923 is an equidigital number, since it uses as much as digits as its factorization.
115032215855923 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3240000, while the sum is 52.
The spelling of 115032215855923 in words is "one hundred fifteen trillion, thirty-two billion, two hundred fifteen million, eight hundred fifty-five thousand, nine hundred twenty-three".
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