Base | Representation |
---|---|
bin | 110101100100010100… |
… | …0100001000100101001 |
3 | 101222221000001100121222 |
4 | 1223020220201010221 |
5 | 3341043003322441 |
6 | 124502455511425 |
7 | 11211452121002 |
oct | 1531050410451 |
9 | 358830040558 |
10 | 115035214121 |
11 | 44871419aa3 |
12 | 1a365088575 |
13 | ab03737b49 |
14 | 57d3c101a9 |
15 | 2ed41a7d4b |
hex | 1ac8a21129 |
115035214121 has 2 divisors, whose sum is σ = 115035214122. Its totient is φ = 115035214120.
The previous prime is 115035214103. The next prime is 115035214157. The reversal of 115035214121 is 121412530511.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 73747006096 + 41288208025 = 271564^2 + 203195^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-115035214121 is a prime.
It is not a weakly prime, because it can be changed into another prime (115035214181) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57517607060 + 57517607061.
It is an arithmetic number, because the mean of its divisors is an integer number (57517607061).
Almost surely, 2115035214121 is an apocalyptic number.
It is an amenable number.
115035214121 is a deficient number, since it is larger than the sum of its proper divisors (1).
115035214121 is an equidigital number, since it uses as much as digits as its factorization.
115035214121 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1200, while the sum is 26.
Adding to 115035214121 its reverse (121412530511), we get a palindrome (236447744632).
The spelling of 115035214121 in words is "one hundred fifteen billion, thirty-five million, two hundred fourteen thousand, one hundred twenty-one".
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