Base | Representation |
---|---|
bin | 10000101111010110011… |
… | …001110110110000100011 |
3 | 11001222021002211000001211 |
4 | 100233112121312300203 |
5 | 122321410430321042 |
6 | 2240244241010551 |
7 | 146052554211652 |
oct | 20572631666043 |
9 | 4058232730054 |
10 | 1150353370147 |
11 | 403953540293 |
12 | 166b43023a57 |
13 | 84629b11157 |
14 | 3d96ab01199 |
15 | 1edcb398017 |
hex | 10bd6676c23 |
1150353370147 has 2 divisors, whose sum is σ = 1150353370148. Its totient is φ = 1150353370146.
The previous prime is 1150353370097. The next prime is 1150353370211. The reversal of 1150353370147 is 7410733530511.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1150353370147 - 215 = 1150353337379 is a prime.
It is not a weakly prime, because it can be changed into another prime (1150353370847) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 575176685073 + 575176685074.
It is an arithmetic number, because the mean of its divisors is an integer number (575176685074).
Almost surely, 21150353370147 is an apocalyptic number.
1150353370147 is a deficient number, since it is larger than the sum of its proper divisors (1).
1150353370147 is an equidigital number, since it uses as much as digits as its factorization.
1150353370147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 132300, while the sum is 40.
The spelling of 1150353370147 in words is "one trillion, one hundred fifty billion, three hundred fifty-three million, three hundred seventy thousand, one hundred forty-seven".
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