Base | Representation |
---|---|
bin | 110101100100010101… |
… | …1101010000000010101 |
3 | 101222221001121011121012 |
4 | 1223020223222000111 |
5 | 3341043211142031 |
6 | 124502525302005 |
7 | 11211462116324 |
oct | 1531053520025 |
9 | 358831534535 |
10 | 115036037141 |
11 | 44871931383 |
12 | 1a365404905 |
13 | ab0396563c |
14 | 57d3d860bb |
15 | 2ed42bbb2b |
hex | 1ac8aea015 |
115036037141 has 4 divisors (see below), whose sum is σ = 115036911852. Its totient is φ = 115035162432.
The previous prime is 115036037093. The next prime is 115036037153. The reversal of 115036037141 is 141730630511.
It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.
It can be written as a sum of positive squares in 2 ways, for example, as 83734996900 + 31301040241 = 289370^2 + 176921^2 .
It is a cyclic number.
It is not a de Polignac number, because 115036037141 - 210 = 115036036117 is a prime.
It is a super-3 number, since 3×1150360371413 (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 115036037098 and 115036037107.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (115036037161) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 195506 + ... + 517971.
It is an arithmetic number, because the mean of its divisors is an integer number (28759227963).
Almost surely, 2115036037141 is an apocalyptic number.
It is an amenable number.
115036037141 is a deficient number, since it is larger than the sum of its proper divisors (874711).
115036037141 is an equidigital number, since it uses as much as digits as its factorization.
115036037141 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 874710.
The product of its (nonzero) digits is 7560, while the sum is 32.
Adding to 115036037141 its reverse (141730630511), we get a palindrome (256766667652).
The spelling of 115036037141 in words is "one hundred fifteen billion, thirty-six million, thirty-seven thousand, one hundred forty-one".
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