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1150362131 is a prime number
BaseRepresentation
bin100010010010001…
…0010001000010011
32222011121110011212
41010210102020103
54323443042011
6310052130335
740335626312
oct10444221023
92864543155
101150362131
11540393106
122813069ab
13154434b69
14acacc279
156aed308b
hex44912213

1150362131 has 2 divisors, whose sum is σ = 1150362132. Its totient is φ = 1150362130.

The previous prime is 1150362127. The next prime is 1150362179. The reversal of 1150362131 is 1312630511.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1150362131 - 22 = 1150362127 is a prime.

It is a super-2 number, since 2×11503621312 = 2646666064877722322, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1150362097 and 1150362106.

It is not a weakly prime, because it can be changed into another prime (1150362121) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 575181065 + 575181066.

It is an arithmetic number, because the mean of its divisors is an integer number (575181066).

Almost surely, 21150362131 is an apocalyptic number.

1150362131 is a deficient number, since it is larger than the sum of its proper divisors (1).

1150362131 is an equidigital number, since it uses as much as digits as its factorization.

1150362131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 540, while the sum is 23.

The square root of 1150362131 is about 33916.9888256608. The cubic root of 1150362131 is about 1047.7995128959.

Adding to 1150362131 its reverse (1312630511), we get a palindrome (2462992642).

The spelling of 1150362131 in words is "one billion, one hundred fifty million, three hundred sixty-two thousand, one hundred thirty-one".